Integrand size = 36, antiderivative size = 156 \[ \int \tan ^{\frac {3}{2}}(c+d x) (a+i a \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=\frac {4 \sqrt [4]{-1} a^2 (A-i B) \arctan \left ((-1)^{3/4} \sqrt {\tan (c+d x)}\right )}{d}+\frac {4 a^2 (A-i B) \sqrt {\tan (c+d x)}}{d}+\frac {4 a^2 (i A+B) \tan ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 A-9 i B) \tan ^{\frac {5}{2}}(c+d x)}{35 d}+\frac {2 i B \tan ^{\frac {5}{2}}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )}{7 d} \]
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Time = 0.50 (sec) , antiderivative size = 156, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.139, Rules used = {3675, 3673, 3609, 3614, 211} \[ \int \tan ^{\frac {3}{2}}(c+d x) (a+i a \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=\frac {4 \sqrt [4]{-1} a^2 (A-i B) \arctan \left ((-1)^{3/4} \sqrt {\tan (c+d x)}\right )}{d}-\frac {2 a^2 (7 A-9 i B) \tan ^{\frac {5}{2}}(c+d x)}{35 d}+\frac {4 a^2 (B+i A) \tan ^{\frac {3}{2}}(c+d x)}{3 d}+\frac {4 a^2 (A-i B) \sqrt {\tan (c+d x)}}{d}+\frac {2 i B \tan ^{\frac {5}{2}}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )}{7 d} \]
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Rule 211
Rule 3609
Rule 3614
Rule 3673
Rule 3675
Rubi steps \begin{align*} \text {integral}& = \frac {2 i B \tan ^{\frac {5}{2}}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )}{7 d}+\frac {2}{7} \int \tan ^{\frac {3}{2}}(c+d x) (a+i a \tan (c+d x)) \left (\frac {1}{2} a (7 A-5 i B)+\frac {1}{2} a (7 i A+9 B) \tan (c+d x)\right ) \, dx \\ & = -\frac {2 a^2 (7 A-9 i B) \tan ^{\frac {5}{2}}(c+d x)}{35 d}+\frac {2 i B \tan ^{\frac {5}{2}}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )}{7 d}+\frac {2}{7} \int \tan ^{\frac {3}{2}}(c+d x) \left (7 a^2 (A-i B)+7 a^2 (i A+B) \tan (c+d x)\right ) \, dx \\ & = \frac {4 a^2 (i A+B) \tan ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 A-9 i B) \tan ^{\frac {5}{2}}(c+d x)}{35 d}+\frac {2 i B \tan ^{\frac {5}{2}}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )}{7 d}+\frac {2}{7} \int \sqrt {\tan (c+d x)} \left (-7 a^2 (i A+B)+7 a^2 (A-i B) \tan (c+d x)\right ) \, dx \\ & = \frac {4 a^2 (A-i B) \sqrt {\tan (c+d x)}}{d}+\frac {4 a^2 (i A+B) \tan ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 A-9 i B) \tan ^{\frac {5}{2}}(c+d x)}{35 d}+\frac {2 i B \tan ^{\frac {5}{2}}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )}{7 d}+\frac {2}{7} \int \frac {-7 a^2 (A-i B)-7 a^2 (i A+B) \tan (c+d x)}{\sqrt {\tan (c+d x)}} \, dx \\ & = \frac {4 a^2 (A-i B) \sqrt {\tan (c+d x)}}{d}+\frac {4 a^2 (i A+B) \tan ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 A-9 i B) \tan ^{\frac {5}{2}}(c+d x)}{35 d}+\frac {2 i B \tan ^{\frac {5}{2}}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )}{7 d}+\frac {\left (28 a^4 (A-i B)^2\right ) \text {Subst}\left (\int \frac {1}{-7 a^2 (A-i B)+7 a^2 (i A+B) x^2} \, dx,x,\sqrt {\tan (c+d x)}\right )}{d} \\ & = \frac {4 \sqrt [4]{-1} a^2 (A-i B) \arctan \left ((-1)^{3/4} \sqrt {\tan (c+d x)}\right )}{d}+\frac {4 a^2 (A-i B) \sqrt {\tan (c+d x)}}{d}+\frac {4 a^2 (i A+B) \tan ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 A-9 i B) \tan ^{\frac {5}{2}}(c+d x)}{35 d}+\frac {2 i B \tan ^{\frac {5}{2}}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )}{7 d} \\ \end{align*}
Time = 2.13 (sec) , antiderivative size = 111, normalized size of antiderivative = 0.71 \[ \int \tan ^{\frac {3}{2}}(c+d x) (a+i a \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=\frac {2 a^2 \left ((105+105 i) \sqrt {2} (i A+B) \text {arctanh}\left (\frac {(1+i) \sqrt {\tan (c+d x)}}{\sqrt {2}}\right )+\sqrt {\tan (c+d x)} \left (210 (A-i B)+70 (i A+B) \tan (c+d x)-21 (A-2 i B) \tan ^2(c+d x)-15 B \tan ^3(c+d x)\right )\right )}{105 d} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 274 vs. \(2 (130 ) = 260\).
Time = 0.04 (sec) , antiderivative size = 275, normalized size of antiderivative = 1.76
method | result | size |
derivativedivides | \(\frac {a^{2} \left (-\frac {2 B \left (\tan ^{\frac {7}{2}}\left (d x +c \right )\right )}{7}+\frac {4 i B \left (\tan ^{\frac {5}{2}}\left (d x +c \right )\right )}{5}-\frac {2 A \left (\tan ^{\frac {5}{2}}\left (d x +c \right )\right )}{5}+\frac {4 i A \left (\tan ^{\frac {3}{2}}\left (d x +c \right )\right )}{3}+\frac {4 B \left (\tan ^{\frac {3}{2}}\left (d x +c \right )\right )}{3}-4 i B \left (\sqrt {\tan }\left (d x +c \right )\right )+4 A \left (\sqrt {\tan }\left (d x +c \right )\right )+\frac {\left (2 i B -2 A \right ) \sqrt {2}\, \left (\ln \left (\frac {1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}+\frac {\left (-2 i A -2 B \right ) \sqrt {2}\, \left (\ln \left (\frac {1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}\right )}{d}\) | \(275\) |
default | \(\frac {a^{2} \left (-\frac {2 B \left (\tan ^{\frac {7}{2}}\left (d x +c \right )\right )}{7}+\frac {4 i B \left (\tan ^{\frac {5}{2}}\left (d x +c \right )\right )}{5}-\frac {2 A \left (\tan ^{\frac {5}{2}}\left (d x +c \right )\right )}{5}+\frac {4 i A \left (\tan ^{\frac {3}{2}}\left (d x +c \right )\right )}{3}+\frac {4 B \left (\tan ^{\frac {3}{2}}\left (d x +c \right )\right )}{3}-4 i B \left (\sqrt {\tan }\left (d x +c \right )\right )+4 A \left (\sqrt {\tan }\left (d x +c \right )\right )+\frac {\left (2 i B -2 A \right ) \sqrt {2}\, \left (\ln \left (\frac {1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}+\frac {\left (-2 i A -2 B \right ) \sqrt {2}\, \left (\ln \left (\frac {1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}\right )}{d}\) | \(275\) |
parts | \(\frac {\left (2 i A \,a^{2}+B \,a^{2}\right ) \left (\frac {2 \left (\tan ^{\frac {3}{2}}\left (d x +c \right )\right )}{3}-\frac {\sqrt {2}\, \left (\ln \left (\frac {1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}\right )}{d}+\frac {\left (2 i B \,a^{2}-A \,a^{2}\right ) \left (\frac {2 \left (\tan ^{\frac {5}{2}}\left (d x +c \right )\right )}{5}-2 \left (\sqrt {\tan }\left (d x +c \right )\right )+\frac {\sqrt {2}\, \left (\ln \left (\frac {1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}\right )}{d}+\frac {A \,a^{2} \left (2 \left (\sqrt {\tan }\left (d x +c \right )\right )-\frac {\sqrt {2}\, \left (\ln \left (\frac {1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}\right )}{d}-\frac {B \,a^{2} \left (\frac {2 \left (\tan ^{\frac {7}{2}}\left (d x +c \right )\right )}{7}-\frac {2 \left (\tan ^{\frac {3}{2}}\left (d x +c \right )\right )}{3}+\frac {\sqrt {2}\, \left (\ln \left (\frac {1-\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}{1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )+\tan \left (d x +c \right )}\right )+2 \arctan \left (1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )+2 \arctan \left (-1+\sqrt {2}\, \left (\sqrt {\tan }\left (d x +c \right )\right )\right )\right )}{4}\right )}{d}\) | \(458\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 501 vs. \(2 (124) = 248\).
Time = 0.29 (sec) , antiderivative size = 501, normalized size of antiderivative = 3.21 \[ \int \tan ^{\frac {3}{2}}(c+d x) (a+i a \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=-\frac {105 \, \sqrt {-\frac {{\left (i \, A^{2} + 2 \, A B - i \, B^{2}\right )} a^{4}}{d^{2}}} {\left (d e^{\left (6 i \, d x + 6 i \, c\right )} + 3 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 3 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \log \left (-\frac {2 \, {\left ({\left (A - i \, B\right )} a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} + \sqrt {-\frac {{\left (i \, A^{2} + 2 \, A B - i \, B^{2}\right )} a^{4}}{d^{2}}} {\left (i \, d e^{\left (2 i \, d x + 2 i \, c\right )} + i \, d\right )} \sqrt {\frac {-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}}{{\left (-i \, A - B\right )} a^{2}}\right ) - 105 \, \sqrt {-\frac {{\left (i \, A^{2} + 2 \, A B - i \, B^{2}\right )} a^{4}}{d^{2}}} {\left (d e^{\left (6 i \, d x + 6 i \, c\right )} + 3 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 3 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \log \left (-\frac {2 \, {\left ({\left (A - i \, B\right )} a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} + \sqrt {-\frac {{\left (i \, A^{2} + 2 \, A B - i \, B^{2}\right )} a^{4}}{d^{2}}} {\left (-i \, d e^{\left (2 i \, d x + 2 i \, c\right )} - i \, d\right )} \sqrt {\frac {-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}}{{\left (-i \, A - B\right )} a^{2}}\right ) - 2 \, {\left ({\left (301 \, A - 337 i \, B\right )} a^{2} e^{\left (6 i \, d x + 6 i \, c\right )} + {\left (679 \, A - 613 i \, B\right )} a^{2} e^{\left (4 i \, d x + 4 i \, c\right )} + {\left (539 \, A - 563 i \, B\right )} a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} + {\left (161 \, A - 167 i \, B\right )} a^{2}\right )} \sqrt {\frac {-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}}{105 \, {\left (d e^{\left (6 i \, d x + 6 i \, c\right )} + 3 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 3 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
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\[ \int \tan ^{\frac {3}{2}}(c+d x) (a+i a \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=- a^{2} \left (\int \left (- A \tan ^{\frac {3}{2}}{\left (c + d x \right )}\right )\, dx + \int A \tan ^{\frac {7}{2}}{\left (c + d x \right )}\, dx + \int \left (- B \tan ^{\frac {5}{2}}{\left (c + d x \right )}\right )\, dx + \int B \tan ^{\frac {9}{2}}{\left (c + d x \right )}\, dx + \int \left (- 2 i A \tan ^{\frac {5}{2}}{\left (c + d x \right )}\right )\, dx + \int \left (- 2 i B \tan ^{\frac {7}{2}}{\left (c + d x \right )}\right )\, dx\right ) \]
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Time = 0.29 (sec) , antiderivative size = 212, normalized size of antiderivative = 1.36 \[ \int \tan ^{\frac {3}{2}}(c+d x) (a+i a \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=-\frac {60 \, B a^{2} \tan \left (d x + c\right )^{\frac {7}{2}} + 84 \, {\left (A - 2 i \, B\right )} a^{2} \tan \left (d x + c\right )^{\frac {5}{2}} + 280 \, {\left (-i \, A - B\right )} a^{2} \tan \left (d x + c\right )^{\frac {3}{2}} - 840 \, {\left (A - i \, B\right )} a^{2} \sqrt {\tan \left (d x + c\right )} - 105 \, {\left (2 \, \sqrt {2} {\left (-\left (i + 1\right ) \, A + \left (i - 1\right ) \, B\right )} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + 2 \, \sqrt {\tan \left (d x + c\right )}\right )}\right ) + 2 \, \sqrt {2} {\left (-\left (i + 1\right ) \, A + \left (i - 1\right ) \, B\right )} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - 2 \, \sqrt {\tan \left (d x + c\right )}\right )}\right ) + \sqrt {2} {\left (\left (i - 1\right ) \, A + \left (i + 1\right ) \, B\right )} \log \left (\sqrt {2} \sqrt {\tan \left (d x + c\right )} + \tan \left (d x + c\right ) + 1\right ) - \sqrt {2} {\left (\left (i - 1\right ) \, A + \left (i + 1\right ) \, B\right )} \log \left (-\sqrt {2} \sqrt {\tan \left (d x + c\right )} + \tan \left (d x + c\right ) + 1\right )\right )} a^{2}}{210 \, d} \]
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Time = 0.96 (sec) , antiderivative size = 160, normalized size of antiderivative = 1.03 \[ \int \tan ^{\frac {3}{2}}(c+d x) (a+i a \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=\frac {\left (2 i - 2\right ) \, \sqrt {2} {\left (i \, A a^{2} + B a^{2}\right )} \arctan \left (-\left (\frac {1}{2} i - \frac {1}{2}\right ) \, \sqrt {2} \sqrt {\tan \left (d x + c\right )}\right )}{d} - \frac {2 \, {\left (15 \, B a^{2} d^{6} \tan \left (d x + c\right )^{\frac {7}{2}} + 21 \, A a^{2} d^{6} \tan \left (d x + c\right )^{\frac {5}{2}} - 42 i \, B a^{2} d^{6} \tan \left (d x + c\right )^{\frac {5}{2}} - 70 i \, A a^{2} d^{6} \tan \left (d x + c\right )^{\frac {3}{2}} - 70 \, B a^{2} d^{6} \tan \left (d x + c\right )^{\frac {3}{2}} - 210 \, A a^{2} d^{6} \sqrt {\tan \left (d x + c\right )} + 210 i \, B a^{2} d^{6} \sqrt {\tan \left (d x + c\right )}\right )}}{105 \, d^{7}} \]
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Time = 10.81 (sec) , antiderivative size = 291, normalized size of antiderivative = 1.87 \[ \int \tan ^{\frac {3}{2}}(c+d x) (a+i a \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=\frac {4\,A\,a^2\,\sqrt {\mathrm {tan}\left (c+d\,x\right )}}{d}+\frac {A\,a^2\,{\mathrm {tan}\left (c+d\,x\right )}^{3/2}\,4{}\mathrm {i}}{3\,d}-\frac {2\,A\,a^2\,{\mathrm {tan}\left (c+d\,x\right )}^{5/2}}{5\,d}-\frac {B\,a^2\,\sqrt {\mathrm {tan}\left (c+d\,x\right )}\,4{}\mathrm {i}}{d}+\frac {4\,B\,a^2\,{\mathrm {tan}\left (c+d\,x\right )}^{3/2}}{3\,d}+\frac {B\,a^2\,{\mathrm {tan}\left (c+d\,x\right )}^{5/2}\,4{}\mathrm {i}}{5\,d}-\frac {2\,B\,a^2\,{\mathrm {tan}\left (c+d\,x\right )}^{7/2}}{7\,d}+\frac {\sqrt {2}\,A\,a^2\,\ln \left (-A\,a^2\,d\,4{}\mathrm {i}+\sqrt {2}\,A\,a^2\,d\,\sqrt {\mathrm {tan}\left (c+d\,x\right )}\,\left (-2+2{}\mathrm {i}\right )\right )\,\left (1-\mathrm {i}\right )}{d}-\frac {\sqrt {-4{}\mathrm {i}}\,A\,a^2\,\ln \left (-A\,a^2\,d\,4{}\mathrm {i}+2\,\sqrt {-4{}\mathrm {i}}\,A\,a^2\,d\,\sqrt {\mathrm {tan}\left (c+d\,x\right )}\right )}{d}+\frac {\sqrt {2}\,B\,a^2\,\ln \left (-4\,B\,a^2\,d+\sqrt {2}\,B\,a^2\,d\,\sqrt {\mathrm {tan}\left (c+d\,x\right )}\,\left (-2-2{}\mathrm {i}\right )\right )\,\left (1+1{}\mathrm {i}\right )}{d}-\frac {\sqrt {4{}\mathrm {i}}\,B\,a^2\,\ln \left (-4\,B\,a^2\,d+2\,\sqrt {4{}\mathrm {i}}\,B\,a^2\,d\,\sqrt {\mathrm {tan}\left (c+d\,x\right )}\right )}{d} \]
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